seq = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] num = 3 [seq[i::num] for i in range(num)]
The result is
[[1, 4, 7, 10], [2, 5, 8], [3, 6, 9]]
CategoryComputing.Lang.Python
seq = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] num = 3 [seq[i::num] for i in range(num)]
The result is
[[1, 4, 7, 10], [2, 5, 8], [3, 6, 9]]